. Now, according to the 1st law of thermodynamics: i.e. . MCQ Questions for Class 11 Physics with Answers were prepared based on the latest exam pattern. All the solutions of Thermodynamics - Physics explained in detail by experts to help students prepare for their CBSE exams. (Molecular mass of N2 = 28; R = 8.3 J mol-1 K-1.) Chapter 12 Thermodynamics. We have provided Thermodynamics Class 11 Physics MCQs Questions with Answers to help students understand the concept very well. NCERT Solutions For Class 11 Physics Chapter 12 PDF Download. CBSE Class 11-science Videos. Thermodynamics is a macroscopic science. How much heat is wasted per minute? Answer: Question 12. NCERT Solutions for Class 11 Physics Chapter 12. The branch of physics which deals with the study of transformation of heat into other forms of energy and vice-versa is called thermodynamics. When the driver is driving a vehicle then due to the motion of air molecules the air temperature inside the tyre increases. Now, according to the first law of thermodynamics: Therefore, the rate at which the internal energy of an electric heater is increasing = 30 W. Q.9: A thermodynamic system is taken from an original state to an intermediate state by the linear process shown in the figure. Solved Problems on Thermodynamics:-Problem 1:-A container holds a mixture of three nonreacting gases: n 1 moles of the first gas with molar specific heat at constant volume C 1, and so on.Find the molar specific heat at constant volume of the mixture, in terms of the molar specific heats and quantitites of the three separate gases. CBSE recommends NCERT books and most of the questions in CBSE exam are asked from NCERT text books. NCERT solutions for Class 11 Physics Textbook chapter 12 (Thermodynamics) include all questions with solution and detail explanation. The walls of the cylinder are made of a heat insulator, and the piston is insulated by having a pile of sand on it. (Take 1 cal = 4.19 J). . A harbour town has a more temperate climate than a desert town which is at the same latitude the harbour town is. The relative humidity in a harbour town is more than that of the relative humidity in a desert town. A geyser heats water flowing at the rate of 3.0 litres per minute from (27 °C to 77 °C) If the geyser operates on a gas burner, what is the rate of consumption of the fuel if its heat of combustion is 4.0 × 10 4 J/g?. In India, CBSE is one of the most widely accepted educational boards in the country. ΔU=0\Delta U=0ΔU=0. Since, the initial pressure of the gas in cylinder P is 1 atm. c) There will be no change in the temperature of the gas. If you have any query regarding NCERT Solutions for Class 11 Physics Chapter 12 Thermodynamics, drop a comment below and we will get back to you at the earliest. Rajasthan Board RBSE Class 11 Physics Chapter 13 Thermodynamics RBSE Class 11 Physics Chapter 13 Textbook Exercises With Solutions RBSE Class 11 Physics Chapter 13 Very Short Answer Type Questions. Class 11 Physics Chapter 12 Thermodynamics teaches you that Thermodynamics is the branch of physics that deals with the concepts of heat and temperature and the inter-conversion of heat and other forms of energy. (d) The expansion is a free expansion. The Second Law of Thermodynamics states that the state of entropy of the entire universe, as an isolated system, will always increase over time. This work done is transformed into heat, due to which temperature of the car types increases. CBSE Class 11-Physics: Thermodynamics Problem's: Questions Doorsteptutor material for CBSE is prepared by world's top subject experts: fully solved questions with step-by-step explanation - practice your way to success. If the geyser operates on a gas burner, what is the rate of consumption of the fuel if its heat of combustion is 4.0 × 104 J/g? ), Universal gas Constant, R = 8.3 J mol – 1 K – 1, Mass of Nitrogen, m = 1.8 × 10 – 2 kg = 18 g, Now, the number of moles, n = mass  of  N2Molicular  mass  of  N2=mM=1828\frac{mass\;of\;N_{2}}{Molicular\;mass\;of\;N_{2}}=\frac{m}{M}=\frac{18 }{28}MolicularmassofN2​massofN2​​=Mm​=2818​, Now, for Nitrogen Molar specific heat at constant pressure CP = 72×R=72×8.3\frac{7}{2}\times R=\frac{7}{2}\times 8.327​×R=27​×8.3. Answer: Question 12. m = 4000 g/min    [Since, 1L = 1000 g], Since, total heat used, Δ\DeltaΔQ = m × c × Δ\DeltaΔT, Therefore, Δ\DeltaΔQ = 4000 × 4.2 × 48 = 8.064 × 105 J/min, Therefore, the Rate of consumption of fuel = 8.064×1044.0×104=2.016  \boldsymbol{\frac{8.064 \times 10^{4}}{4.0 \times 10^{4} }=2.016\;}4.0×1048.064×104​=2.016g/min, Q.2: What amount of heat must be supplied to 2.0 × 10–2 kg of nitrogen (at room temperature) to raise its temperature by 45 °C at constant pressure ? Question 12.1 A geyser heats water flowing at the rate of 3.0 litres per minute from 27 °C to 77 °C. Thermodynamics is concerned with the work done by a system and the heat it exchanges with its surroundings. 9 A thermodynamic system is taken from an original state to an intermediate state by the linear process shown in Fig.Its volume is then reduced to the original value from E to F by an isobaric process. Answer:  (a) Since the final temperature and initial temperature remain the same, Thermodynamics is the branch of physics that deals with the concepts of heat and temperature, and the inter-conversion of heat and other forms of energy. ... NCERT Solutions Click Here. The process described above is an Adiabatic process, as the cylinder is completely insulated from its surrounding and because of that, there is no exchange of heat between the surroundings and the system. NCERT Solutions For Class 11 Physics Thermodynamics Class 11 Physics Class book solutions are available in PDF format for free download. Since in this case, no work is done by the gas or on the gas. Equilibrium in thermodynamics refers to the situation when state variables describing the thermodynamic state of a system is independent of time. From the above figure, the Total work done by the gas from A to B to C = Area of triangle ABC. Question1. Heat By what factor does the pressure of the gas increase if the gas is compressed to half its original volume? CBSE Class 11 Physics Notes : Thermodynamics. 6 Two cylinders A and B of equal capacity are connected to each other via a stopcock. thermodynamics and express it mathematically; • calculate energy changes as ... CBSE Class 11 Physics. CBSE Class 11-science … 2 What amount of heat must be supplied to 2.0 x 10-2 kg of nitrogen (at room temperature) to raise its temperature by 45 °C at constant pressure? How much heat is wasted per minute? Therefore it is crucial to study the solutions of this chapter. CBSE Class 11 Chemistry , CBSE Class 11 Physics. Here on AglaSem Schools, you can access to NCERT Book Solutions in free pdf for Physics for Class 11 so that you can refer them as and when required. A contains a gas at standard temperature and pressure. We hope the NCERT Solutions for Class 11 Physics Chapter 12 Thermodynamics help you. 15. (ii).The coolant used in a chemical or nuclear plant should always have a high specific heat. (c) The system being thermally insulated, there is no change in temperature (because of free expansion) Answer the following : When two bodies having different temperatures say, T1 and T2 are brought in thermal contact with each other, there is a flow of heat from the body at the higher temperature to the body at the lower temperature till both the body reaches to an equilibrium position, i.e., both the bodies are having equal temperature. Now, the total amount of heat that is to be supplied to increase its temperature by 50 °C: Therefore, the total amount of heat that is to be supplied to raise the temperature of Nitrogen by 50 °C = 933.9575 J. Q.3: Explain why Thermodynamics is one of the most scoring subjects in Physics. Comment. NCERT Solutions for Class 11 Physics Chapter 12 will strengthen a student’s ability to grasp this chapter of Physics. Therefore the efficiency of the steam engine is 16.57% and the amount of heat that is wasted per minute is 2.92×109 J. Q.8: An electric heater supplies heat to a system at a rate of 100W. Thermodynamics Physics First law Second Law Zero Law Cp Cv Work Heat Thermal Equilibrium Carnot's Heat Engine Isothermal Adiabatic If you have any query regarding NCERT Solutions for Class 11 Physics Chapter 12 Thermodynamics, drop a comment below and we will get back to you at the earliest. NCERT Solutions for Class 11 Physics Chapter 12 Thermodynamics are part of Class 11 Physics NCERT Solutions. It is because during the expansion of gas there is no work being done by the gas. At what rate is the internal energy increasing? Study notes & practice Thermodynamics sample question papers to score high in school board exams. This is possible because of the infinitesimal difference in temperature between the system and the reservoir. PDF to download free. And Δ\DeltaΔW = -23.2 J, because the work is done by the system. (c) Air pressure in a car tyre increases during driving. NCERT Solutions for Class 11-science Physics CBSE, 12 Thermodynamics. (Take 1 cal = 4.19 J) If you have any query regarding NCERT Solutions for Class 11 Physics Chapter 12 Thermodynamics, drop a comment below and we will get back to you at the earliest. As a result, the gas can not return to an equilibrium state which lie on the P-V-T surface. Before we discussed the Pradeep Book Solution for Class 11. students are advised to check out the complete syllabus.. CBSE Useful Resources. Therefore, the percentage efficiency of the engine is 16.57 %. NCERT Book Class 11 Physics Chapter 12 Thermodynamics SHARES. According to zeroth law of thermodynamics, when a hot substance is placed in contact with a cold substance, heat flows from hot to the cold substances. Thermodynamics : NCERT Solution - Class 11 Physics. Also after the chapter you can get links to Class 11 Physics Notes, NCERT Solutions, Important Question, Practice Papers etc. These are the Thermodynamics class 11 Notes Physics prepared by team of expert teachers. The walls of the cylinder are made of a heat insulator, and the piston is insulated by having a pile of sand on it. Now, the amount of heat wasted = (3.5 × 109 – 5.8 × 108) = 2.92×109 J. These ncert book chapter wise questions and answers are very helpful for CBSE exam. This NCERT solution consists of answers to the questions provided in the textbook, important questions in previous year question papers and CBSE sample papers. A contains a gas at standard temperature and pressure. Students can also download NCERT Solutions for Class 11 Physics Physics Chapter 12 Thermodynamics … (a) What is the final pressure of the gas in A and B? ΔU=ΔQ−ΔW\Delta U=\Delta Q-\Delta WΔU=ΔQ−ΔW= 0 – ( -23.2 ). NCERT Solutions for Class 11 Physics Chapter 12 Thermodynamics will give you the self-confidence to face Class 11 examination and entrance examination. NCERT Class 11 Physics Notes | Textbook | Solution | | Exemplar | Exemplar Solution | Quick Notes | Short Notes | Model Paper and Many More Reading Material are Added for CBSE Students. This would prevent different parts of the plant from getting too hot. If you have any query regarding NCERT Solutions for Class 11 Physics Chapter 12 Thermodynamics, drop a comment below and we will get back to you at the earliest. Students can avail BYJU’S interactive videos, animations and info-graphics that help them remember the concepts for a long period. Question 12.1 A geyser heats water flowing at the rate of 3.0 litres per minute from 27 °C to 77 °C. (b) This is because heat absorbed by a substance is directly proportional to the specific heat of the substance. (c) When car is driven, some work is being done on types in order to overcome dissipative forces of friction and air resistance etc. Nageen Prakashan Physics Ch-19 Thermodynamics Nootan Solutions ISC Class-11. It is because the internal energy can change only when the work is done by the system or on the system. The temperature of a body is related to its average internal energy, not to the kinetic energy of motion of its centre of mass. (d) The climate of a harbour town is more temperate than that of a town in a desert at the same latitude. . Required fields are marked *, Thermodynamic state variables and the equation of state. Now, Area of triangle ABC = 12\frac{1}{2}21​ × AC × BC, Where, AC = Change in pressure and BC = Change in volume, Now, the Area of triangle ABC = 12\frac{1}{2}21​ × AC × BC, Therefore, the Total work done by the gas from A to B to C is 800 J. Q.10: A refrigerator is to maintain eatables kept inside at 90C. Students can avail BYJU’S interactive videos, animations and info-graphics that help them remember the concepts for a long period. These solutions for Thermodynamics are extremely popular among Class 11 Science students for Physics Thermodynamics Solutions come handy for quickly completing your homework and preparing for exams. Answer: Volume of water heated = 3.0 litre per minute Mass of water heated, m = 3000 g per minute Increase in temperature. NCERT Solutions for Class 11 Physics in PDF format are available to download updated for new academic session 2020-2021, solutions of Exercises, Additional Exercises, ... Thermodynamics: It is the theory of heat, temperature and conversion of heat into work and vice-versa. It is a macroscopic science, which involves the macroscopic variables, such as pressure, temperature, volume etc., while describing the state of … In isothermal quasi-static processes, heat is absorbed or given out by the system even though at every stage the gas has the same temperature as that of the surrounding reservoir. In this chapter, you will study about laws of thermodynamics, thermal equilibrium, heat capacity, and various other topics. (Molecular mass of N2 = 28; R = 8.3 J mol–1 K–1. Physics Chapter 12 in Class 11 is given here so that students can prepare effectively for their exam. Here, in this case, the internal energy of the gas will not change i.e. NCERT Solutions for Class 11 Physics Chapter 12 Thermodynamics. Download free NCERT Solutions Class 11 Chapter 12 Thermodynamics in PDF form solved by NCERT (CBSE) experts teachers. This will clear students doubts about any question and improve application skills while preparing for board exams. B is completey evacuated. If the geyser operates on a gas burner, ... From the first law of thermodynamics, we have: Reading Time: 8min read 0. (b) What is the change in internal energy of the gas? Q.5: In changing the state of a gas adiabatically from an equilibrium state A to another equilibrium state B, an amount of work equal to 22.3 J is done on the system. . NCERT Solutions for Class 11 Physics Physics Chapter 12 Thermodynamics includes all the important topics with detailed explanation that aims to help students to understand the concepts better. Now, since this process is an Adiabatic process. Thermodynamics Class 11th. Question 12. Why? View all Physics important questions for all the chapters. NCERT Solutions For Class 11 Physics Chapter 12 PDF Download. Work done by the steam engine, W = 5.4 × 108 J per minute, Heat supplied from the boiler, H = 3.6 × 109 J per minute, ⇒Output  EnergyInput  Energy=5.8×108  J3.5×109  J=0.1657\Rightarrow \frac{Output\;Energy}{Input\;Energy}=\frac{5.8\times 10^{8}\;J }{3.5\times 10^{9}\;J }=0.1657⇒InputEnergyOutputEnergy​=3.5×109J5.8×108J​=0.1657. Easy notes that contain numerical problems of the chapter. Class 11 Pradeep Physics Solution . In order to get more marks in Class 11 Physics, it is crucial to study these solutions as one can expect many questions from this resource being asked often in entrance exams and competitive exams. Q.4: A cylinder with a movable piston contains 3 moles of hydrogen at standard temperature and pressure. NCERT Solutions Class 11 Physics Chapter 12 Thermodynamics. (iii). The best app for CBSE students now provides Thermodynamics class 11 Notes Physics latest chapter wise notes for quick preparation of CBSE exams and school based annual examinations. Now, as soon as the stop cock is opened the gas will start flowing from cylinder P to cylinder Q which is completely evacuated and thus the volume of the gas will be doubled because both the cylinders have equal capacity. (i). A geyser heats water flowing at … This solution comes with examples to help a student in revision and score better. (a) What is the final pressure of the gas in A and B ? Class 11 Physics NCERT solution app is developed as per the requirements of our CBSE students to solve maths problem effectively and in real time with better understanding. CBSE Physics Chapter 12 Thermodynamics class 11 Notes Physics in PDF are available for free download in myCBSEguide mobile app. branch of physics which is concerned with the relationship between other forms of energy and heat (d) Do the intermediate states of the system (before settling to the final equilibrium state) lie on its P-V-T surface? 10 A refrigerator is to maintain eatables kept inside at 9 °C, if room temperature is 36 °C. Thermodynamics is the hot topic for the experts who prepare question papers. This PDF file for 11th class physics subject contains solutions for all questions in the NCERT text book. by Neepur Garg. Download PDF solutions for class 11th Physics chapter 12 Thermodynamics from eCareerPoint to prepare for your exams. The syllabus covered by this board is also helpful in attending other competitive exams such as JEE and NEET. Heat (c) What is the change in the temperature of the gas? NCERT Solutions for Class 11 Physics in PDF format are available to download updated for new academic session 2020-2021, solutions of Exercises, Additional Exercises, Supplementary material and NCERT books 2020-2021. The stopcock is suddenly opened. Download revision notes for Thermodynamics class 11 Notes Physics and score high in exams. Chemistry Notes , Chemistry Assignment , Chemistry Quiz , NCERT Solution NCERT Books Class 11 Physics: The National Council of Educational Research and Training (NCERT) publishes Physics textbooks for Class 11. Some key points of Thermodynamics are given below. Equilibrium in thermodynamics refers to the situation when macroscopic variables describing the thermodynamic state of a system is not depended on time. Answer: Question 12. 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